A transformer having efficiency of 90% is working on 200 V and 3 kW power supply. If the current in the secondary coil is 6 A, the voltage across the secondary coil and the current in the primary coil respectively are :
A
450V and 15A
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B
200V and 1A
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C
400V and 9A
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D
250V and 8A
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Solution
The correct option is A450V and 15A Pin=IpVp⇒Tp=PinVp=3000W200N=15AEfficciencyofthetransformerη=PoutPin=VsIsVpIp⇒90100=6Vs3000Vs=90×5000100×6=450V