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Kirchhoff's Junction Law

A transistor ...

Question

A transistor has a base current of $1 m A$ and emitter current $90 m A$ . The collector current will be

A

90 m A

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B

1 m A

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C

89 m A

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D

91 m A

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Solution

The correct option is B $89 m A$
Given: Base current, $I_{b} = 1 m A$ and emittter current $I_{e} = 90 m A$
Let collector current be $I_{c}$
Using, $I_{e} = I_{b} + I_{c}$
$90 = 1 + I_{c} ⟹ I_{c} = 89 m A$

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