Question

Consider an n-p-n transistor amplifier in common emitter configuration. The current gain of the transistor is $100$. If the collector current changes by $1mA$, what will be the change in emitter current

• A. $1.1mA$
• B. $1.01mA$
• C. $0.01mA$
• D. $10mA$

Answer 1

Answer: (B)

$1.01mA$

$100=\frac{\Delta I_c}{\Delta I_b}$ $\Rightarrow$ $\Delta I_b=\frac{1}{100}mA=0.01mA$
$\Delta I_e=\Delta I_c+\Delta I_b=1+0.01=1.01mA$