A transistor is connected in common emitter CE configuration- The collector supply is 8V and the voltage drop across a resistor of 800 - in the collector circuit is 0-8 V- If the current gain factor - is 0-96- then the change in base current is

The correct option is A 124mA The collector current, I_C=V_CER_E #160; =8V800Ω #160; =1mA The current gain, β=I_CI_B Since, β ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

P-N Junction

A transistor ...

Question

A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of $800 Ω$ in the collector circuit is 0.8 V. If the current gain factor ( $α$ ) is 0.96, then the change in base current is

\frac{1}{24} m A

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{1}{12} m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{6} m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{3} m A

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{1}{24} m A$
The collector current, $I_{C} = \frac{V_{C E}}{R_{E}}$ $= \frac{8 V}{800 Ω}$ $= 1 m A$
The current gain, $β = \frac{I_{C}}{I_{B}}$
Since, $β = \frac{α}{1 α} = \frac{0.96}{1 - 0.96} = 24$

Hence, $I_{B} = \frac{I_{C}}{β}$ $= \frac{1}{24} m A$

Suggest Corrections

Similar questions

Q. A transistor is connected in common-emitter (C-E) configuration. The collector supply is 8V and the voltage drop across a resistor of 800

Ω

in the collector circuit is 0.5V. If the current gain factor

(α)

is 0.96, find the base current.

Q. In a common emitter configuration of a transistor, the voltage drop across a

500 Ω

resistor in the collector circuit is

0.5 V

. When the collector supply voltage is

0.96 V

and

α = 0.96

, then the base current is

Q. A N-P-N transistor is connected in common emitter configuration in which collector supply is

8 v o l t

and the voltage drop across the load resistor of

800 o h m

connected to the collector circuit is

0.8 v o l t .

If current amplification factor

α

\frac{25}{26}

and the input resistance of the transistor is

200 o h m

then the collector emitter voltage, base current, the voltage and power gain are

Q. For a transistor, the current amplification factor is

0.8

. The transistor is connected in common emitter configuration, the change in collector current when the base current changes by

6 m A

For a transistor, the current amplification factor(α) is 0.8. The transistor is connected in common emitter configuration. The change in collector current, when the base current changes by 6 mA is

Join BYJU'S Learning Program

A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of 800Ω in the collector circuit is 0.8 V. If the current gain factor (α) is 0.96, then the change in base current is

The correct option is A 124mAThe collector current, IC=VCERE =8V800Ω =1mAThe current gain, β=ICIBSince, β=α1α=0.961−0.96=24Hence, IB=ICβ =124mA

A transistor is connected in common emitter (CE) configuration. The collector supply is 8V and the voltage drop across a resistor of $800 Ω$ in the collector circuit is 0.8 V. If the current gain factor ( $α$ ) is 0.96, then the change in base current is

The correct option is A $\frac{1}{24} m A$
The collector current, $I_{C} = \frac{V_{C E}}{R_{E}}$ $= \frac{8 V}{800 Ω}$ $= 1 m A$
The current gain, $β = \frac{I_{C}}{I_{B}}$
Since, $β = \frac{α}{1 α} = \frac{0.96}{1 - 0.96} = 24$

Hence, $I_{B} = \frac{I_{C}}{β}$ $= \frac{1}{24} m A$