Question

A transistor is working in common emitter mode. Its amplification factor $\left(\beta \right)$ is $80$. If the base current is $250\mu A$, the collector current will be

• A. $1.25\mu A$
• B. $\frac{250}{80}\mu A$
• C. $430\mu A$
• D. $250\times 80\mu A$

Answer 1

The correct option is D $250\times 80\mu A$

Given : $\beta =80$

Base current $I_b=250\mu A$

Collector current $I_c=\beta I_b=80\times 250$ $\mu A$