Question

A transition metal M can exist in two oxidation state $+2$ and $+3$. It forms an oxide whose experimental formula is given by $M_{x}O$ where $x<1$. Then the ratio of metal ions in $+3$ state to those in $+2$ state in oxide is given by:

• A. $\frac{1-x}{1+x}$
• B. $1+2x$
• C. $1+\frac{x}{2}$
• D. $\frac{2(1-x)}{3x-2}$

Answer 1

The correct option is D $\frac{2(1-x)}{3x-2}$

Let the formula of oxide be $M_{x}O$

In $1$ $mol$ $MxO$,

Let no. of mole of $M^{2+}=y$

Let no. of mole of $M^{3+}=x-y$

$\frac{M^{3+}}{M^{2+}}=\frac{x-y}{y}=\frac{x-(3x-2)}{3x-2}=\frac{-2x+2}{3x-2}=\frac{2(1-x)}{3x-2}$