Question

What is x (x = coordination number + the oxidation state) of the central metal ion in $\left[Ni\right(N{H}_3{)}_6{]}^{2+}$ ?

Answer 1

Oxidation number and the coordination number of nickel in $\left[Ni\right(N{H}_3{)}_6{]}^{2+}$ complex are 2 and 6 respectively.

Oxidation number of nickel in $\left[Ni\right(N{H}_3{)}_6{]}^{2+}=$

$x+(0\times 6)=+2$

$x+0=+2$

$x=+2$

Nickel is bounded with six atoms of ammonia which is a monodentate ligand. Thus, coordination number is 6.

The correct answer is 8.