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Question

A transition metal M can exist in two oxidation state +2 and +3. It forms an oxide whose experimental formula is given by MxO where x<1. Then the ratio of metal ions in +3 state to those in +2 state in oxide is given by:

A
1x1+x
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B
1+2x
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C
1+x2
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D
2(1x)3x2
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Solution

The correct option is D 2(1x)3x2
Let the formula of oxide be MxO
In 1 mol MxO,
Let no. of mole of M2+=y
Let no. of mole of M3+=xy
M3+M2+=xyy=x(3x2)3x2=2x+23x2=2(1x)3x2

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