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Standard IX

Chemistry

Chlorides of Phosphorus

A translucent...

Question

A translucent white solid $(A)$ reacts with excess of chlorine to give a yellowish white powder $(B) .$ $(B)$ reacts with organic compounds containing $- O H$ group converting them into chloro derivatives. $(B)$ on hydrolysis gives $(C)$ and is finally converted to phosphoric acid. $(A), (B)$ and $(C)$ are:

P_{4}, P C l_{3}

and

H_{3} P O_{4}

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P_{4}, P C l_{5}

and

H_{3} P O_{3}

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P_{4}, P C l_{5}

and

P O C l_{3}

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P_{4}, P C l_{3}

and

P O C l_{3}

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Solution

The correct option is C $P_{4}, P C l_{5}$ and $P O C l_{3}$
$P_{4} A + 10 C l_{2} \to P C l_{5} B$

$C_{2} H_{5} O H + P C l_{5} B \to C_{2} H_{5} C l + P O C l_{3} + H C l$

$P C l_{5} B + H_{2} O \to P O C l_{3} C + 2 H C l$

$P O C l_{3} C + 3 H_{2} O \to H_{3} P O_{4} + 3 H C l$

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Q. A translucent white waxy solid (A) reacts with excess of chlorine to give a yellowish white powder (B). (B) reacts with organic compounds containing -OH group converting them into chloro derivatives. (B) on hydrolysis gives (C) and is finally converted to phosphoric acid. (A), (B) and (C) are?

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An organic compound A having the molecular formula $C_{3} H_{8} O$ is a liquid at room temperature. The organic liquid A reacts with sodium metal to evolve a gas which burns causing a little explosion. When the organic liquid A is heated with concentrated sulphuric acid at $170^{o} C$ , it forms a compound B which decolourises bromine water. The compound B adds on one molecule of hydrogen in the present of Ni as catalyst to form compound C which gives substitution reactions with chlorine.

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A translucent white solid (A) reacts with excess of chlorine to give a yellowish white powder (B). (B) reacts with organic compounds containing −OH group converting them into chloro derivatives. (B) on hydrolysis gives (C) and is finally converted to phosphoric acid. (A),(B) and (C) are:

The correct option is C P4,PCl5 and POCl3P4A+10Cl2→PCl5B C2H5OH+PCl5B→C2H5Cl+POCl3+HCl PCl5B+H2O→POCl3C+2HCl POCl3C+3H2O→H3PO4+3HCl

The correct option is C $P_{4}, P C l_{5}$ and $P O C l_{3}$
$P_{4} A + 10 C l_{2} \to P C l_{5} B$

$C_{2} H_{5} O H + P C l_{5} B \to C_{2} H_{5} C l + P O C l_{3} + H C l$

$P C l_{5} B + H_{2} O \to P O C l_{3} C + 2 H C l$

$P O C l_{3} C + 3 H_{2} O \to H_{3} P O_{4} + 3 H C l$