A triangle ABC is right-angled at B. AB = 6 cm and BC = 8 cm. What is the length of AC?
10 cm
Given that
A triangle is right-angled at B.
AB = 6 cm and BC = 8 cm.
By Pythagoras theorem,
AB2+BC2=AC2
On substituting the values we get:
62+82=AC2
⇒AC2=100
⇒AC=√100
⇒AC=10