Question

A triangle has an area of 11.6 sq cm. If its height is 2.9 cm, what is its base?

Answer 1

Area of the triangle is 11.6 sq cm.
Height of the triangle is 2.9 cm.
Area of a triangle = $\frac{1}{2}$ × Height × Base
11.6 sq cm = $\frac{1}{2}$ × 2.9 cm × Base
$\mathrm{Height}=\frac{23.2\mathrm{sq}\mathrm{cm}}{2.9\mathrm{cm}}$
∴ Height = 8 cm
∴ The height of the triangle is 8 cm.