A triangular advertisement board has sides 11m,15m and 6m. If the advertisement yields an earning of Rs $\frac{1000}{m^{2}}$ per month.So how much the company will earn in 3 and half years? [3 MARKS]

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Solution

Concept : 0.5 Mark
Application : 0.5 Mark
Calculation : 2 Marks

Semi perimeter of a triangle = $\frac{(a + b + c)}{2}$ $\Rightarrow$ $\frac{(11 + 15 + 6)}{2}$ =16cm

Area of a triangle = $\sqrt{s (s - a) (s - b) (s - c)}$ $\Rightarrow$ $\sqrt{16 (16 - 11) (16 - 15) (16 - 6)}$

$\Rightarrow$ $\sqrt{800}$

$\Rightarrow$ 20 $\sqrt{2}$ $c m^{2}$

If the advertisement yields an earning of Rs $\frac{1000}{m^{2}}$ per month,

Then the earning in 42 months = 20 $\sqrt{2}$ × 1000 × 42 =Rs 840000 $\sqrt{2}$

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A triangular advertisement board has sides 11m,15m and 6m. If the advertisement yields an earning of Rs1000 m2 per month.So how much the company will earn in 3 and half years? [3 MARKS]

A triangular advertisement board has sides 11m,15m and 6m. If the advertisement yields an earning of Rs $\frac{1000}{m^{2}}$ per month.So how much the company will earn in 3 and half years? [3 MARKS]