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Question

The triangular side walls of a flyover have been used for advertisement. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of Rs 5000 per m2 per year. A company hired one of its walls for 3 months. How much rent did it pay?


Solution

The sides of the triangle (i.e., a,b,c) are of 122m, 22m, and 120m respectively.
Perimeter of triangle = ( 122+22+120) m

2s = 264m
S = 132m
By Heron’s formula,
Area of triangle = s(sa)(sb)(sc)
Area of given triangle = 132(132122)(13222)(132120)m2=132(10)(110)(12)m2=1320m2
Rent of 1 m2 area per year = Rs 5000
Rent of 1 m2 area per month = Rs.500012
Rent of 1320 m2 area for 3 months = (Rs.500012×3×1320)
=Rs(5000×330)=Rs.1650000

Therefore, the company has to pay Rs. 1650000.


Physics

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