A triangular tent is 12 ft. high . The diagonal length between the top and the pegs of the tent is 15 ft. Find the base width of the tent if it is given that the height of the tent bisects the base width at right angle.

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Solution

Height of the tent, AD = 12 ft.
Diagonal length, AB = 15 ft.
$∴$ Base length, BC = 2 (BD)
Applying Pythagoras theorem in triangle ABD:
BD = $\sqrt{15^{2} - 12^{2}} = \sqrt{225 - 144} = \sqrt{81} = 9$ =

Therefore, BC = 2 BD = 18 ft.

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