A triode valve has an amplification factor of $20$ and its plate is given a potential of $300 V$ . The grid voltage to reduce the plate current to zero, is

25 V

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15 V

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12 V

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10 V

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Solution

The correct option is B $15 V$
Amplification factor $= 20 = \frac{P l a t e p o t e n t i a l}{G r i d p o t e n t i a l}$
$20 = \frac{300}{V}$ $\Rightarrow$ $V = \frac{300}{20} = 15 V$

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A triode valve has an amplification factor of 20 and its plate is given a potential of 300V. The grid voltage to reduce the plate current to zero, is

The correct option is B 15VAmplification factor =20=PlatepotentialGridpotential20=300V ⇒ V=30020=15V

A triode valve has an amplification factor of $20$ and its plate is given a potential of $300 V$ . The grid voltage to reduce the plate current to zero, is

The correct option is B $15 V$
Amplification factor $= 20 = \frac{P l a t e p o t e n t i a l}{G r i d p o t e n t i a l}$
$20 = \frac{300}{V}$ $\Rightarrow$ $V = \frac{300}{20} = 15 V$