A truck increases its speed from $10 k m / h$ to $50 k m / h$ in $20$ seconds. Its acceleration is:

0.55 m / s^{2}

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2.55 m / s^{2}

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0.75 m / s^{2}

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8.65 m / s^{2}

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Solution

The correct option is B $0.55 m / s^{2}$
Given: Initial speed, $u = 10 k m / h = 10 \times \frac{5}{18} m / s$

Final speed, $v = 50 k m / h = 50 \times \frac{5}{18} m / s$

Using equation of motion,

Acceleration, $a = \frac{v - u}{t}$

$= \frac{\frac{5}{18} \times (50 - 10)}{20}$

$= \frac{5}{18} \times 2$

$= 0.55 m / s^{2}$

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A truck increases its speed from 10km/h to 50km/h in 20 seconds. Its acceleration is:

The correct option is B 0.55m/s2Given: Initial speed, u=10 km/h=10×518m/s Final speed, v=50 km/h=50×518m/sUsing equation of motion, Acceleration, a=v−ut =518×(50−10)20 =518×2 =0.55 m/s2

A truck increases its speed from $10 k m / h$ to $50 k m / h$ in $20$ seconds. Its acceleration is: