A truck is moving with a constant velocity of $54 k m h^{- 1}$ . In what direction should a stone be projected up with a velocity of $20 m s^{- 1}$ , from the floor of the truck, so as to appear at right angles to the truck, for a person standing on earth?

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Solution

Let the stone be projected at an angle a to the direction of motion of truck, with a speed of $20 m s^{- 1}$ .
Since the resultant displacement along horizontal is zero, the velocity along horizontal = 0.
$15 + 20 cos α = 0$
$cos α = - \frac{3}{4} \Rightarrow α = {cos}^{- 1} (- \frac{3}{4})$

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A truck is moving with a constant velocity of 54kmh−1. In what direction should a stone be projected up with a velocity of 20ms−1, from the floor of the truck, so as to appear at right angles to the truck, for a person standing on earth?

Let the stone be projected at an angle a to the direction of motion of truck, with a speed of 20ms−1.Since the resultant displacement along horizontal is zero, the velocity along horizontal = 0.15+20cosα=0cosα=−34⇒α=cos−1(−34)

A truck is moving with a constant velocity of $54 k m h^{- 1}$ . In what direction should a stone be projected up with a velocity of $20 m s^{- 1}$ , from the floor of the truck, so as to appear at right angles to the truck, for a person standing on earth?

Let the stone be projected at an angle a to the direction of motion of truck, with a speed of $20 m s^{- 1}$ .
Since the resultant displacement along horizontal is zero, the velocity along horizontal = 0.
$15 + 20 cos α = 0$
$cos α = - \frac{3}{4} \Rightarrow α = {cos}^{- 1} (- \frac{3}{4})$