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Standard XII

Physics

Relation between Linear and Angular Speed

A truck of ma...

Question

A truck of mass $5 t h o u s a n d k g$ moving at a speed of $20 m / s e c$ . collides with a car of mass thousand kg moving at a speed of $30 m / s e c$ . If the speed of car becomes $10 m / s e c$ after collision. Calculate the speed of truck.

28 m/s

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24 m/s

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30 m/s

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50 m/s

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Solution

The correct option is B 24 m/s
Using conservation of momentum
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$

$\Rightarrow 5000 (20) + 1000 (30) = 5000 (v_{1}) + 1000 (10)$

$\Rightarrow v_{1} = \frac{120000}{5000} = 24 m / s$

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A truck of mass 5 thousand kg moving at a speed of 20 m/sec. collides with a car of mass thousand kg moving at a speed of 30 m/sec. If the speed of car becomes 10 m/sec after collision. Calculate the speed of truck.

The correct option is B 24 m/sUsing conservation of momentum m1u1+m2u2=m1v1+m2v2⇒5000(20)+1000(30)=5000(v1)+1000(10)⇒v1=1200005000=24m/s

A truck of mass $5 t h o u s a n d k g$ moving at a speed of $20 m / s e c$ . collides with a car of mass thousand kg moving at a speed of $30 m / s e c$ . If the speed of car becomes $10 m / s e c$ after collision. Calculate the speed of truck.

The correct option is B 24 m/s
Using conservation of momentum
$m_{1} u_{1} + m_{2} u_{2} = m_{1} v_{1} + m_{2} v_{2}$

$\Rightarrow 5000 (20) + 1000 (30) = 5000 (v_{1}) + 1000 (10)$

$\Rightarrow v_{1} = \frac{120000}{5000} = 24 m / s$