Question

A truck starts from rest and acquires uniform velocity of 54 km/h. During this time, it covers a distance of 240 m.
What is the acceleration produced in the truck?

Answer 1

$$\begin{gathered} \mathrm{Initial}\mathrm{velocity}:\mathrm{u}=0 \\ \mathrm{Final}\mathrm{velocity}: \\ \mathrm{v}=54\mathrm{km}/\mathrm{h} \\ =54\times \frac{5}{18} \\ =15\mathrm{m}/\mathrm{s} \\ \mathrm{Distance}: \\ \mathrm{s}=240\mathrm{m} \\ \mathrm{Equation}\mathrm{to}\mathrm{use}: \\ {\mathrm{v}}^2-{\mathrm{u}}^2=2\mathrm{as} \\ {15}^2-0=2\mathrm{a}\times 240 \\ \mathrm{a}=\frac{225}{480} \\ \mathbf{}\mathbf{=}\mathbf{0}\mathbf{.}\mathbf{469}\mathbf{}\mathbf{m}\mathbf{/}{\mathbf{s}}^{\mathbf{2}} \end{gathered}$$