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Acceleration

A truck trave...

Question

A truck travelling along a straight road at a constant speed of 72kph passes a car at time t=0 moving much slower. At instant the truck passes the car, the car starts accelerating at constant 1m/sq.sec and overtake the truck 0.6km further down the road, from where the car moves uniformly. Find the distance between them at t=50sec

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Solution

$u_{c} = 0 s p p e d o f t r u c k u_{t} = 72 k m / h = 20 m / s f o r t r u c k d i s \tan c e t a r v e l b y t r u c k i n t i m e t = 0.6 k m = 600 m t = \frac{600}{20} = 30 s a i s t h e a c c e l e r a t i o n o f c a r s = u t + \frac{1}{2} a t^{2} 600 = 0 + 0.5 \times a \times 900 a = 4 / 3 m / s^{2} d i s \tan c e t a r v e l b y c a r i n 50 s e c o n d s = \frac{1}{2} \times \frac{4}{3} \times 2500 = 5000 / 3 m d i s \tan c e t r a v e l b y t r u c k i n 50 s e c o n d s = 20 * 50 = 1000 m d i s \tan c e b e t w e e n t h e m = \frac{5000}{3} - 1000 = 2000 / 3 m = 666.66 m$

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