A tuning fork of frequency 480Hz is used in an experiment for measuring speed of sound (v) in air by resonance tube method. Resonance is observed to occur at two successive lengths of the air column, l1=30cm and l2=70cm. Then v is equal to
A
384ms−1
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B
338ms−1
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C
379ms−1
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D
332ms−1
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Solution
The correct option is A384ms−1 Given,
f=480Hz l1=30cm l2=70cm
The speed of sound (v) in air by resonance tube method is given by, v=2f(l2−l1) v=2×480×(70−30)×10−2 v=38400×10−2m/s v=384m/s
Final answer: (c)