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Question

A tuning fork P of frequency 280 Hz produces 6 beats/s with unknown tuning fork Q.
Column-I Column-II
A) P is waxed and number of beats is decreased P) Frequency of Q is 286 Hz
B) Q is filed and and number of beats is decreased Q) Frequency of Q is 274 Hz
C) P is filed and number of beats remains same R) Frequency of Q is 272 Hz
D) Q is filed and number of beats is increased S) Frequency of Q is 282 Hz

A
A-Q, B-R, C-S, D-R
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B
A-Q, B-R, C-Q, D-P
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C
A- PQ, B-QR, C-RS, D-P
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D
A-RS, B-QR, C-S, D-R
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Solution

The correct option is B A-Q, B-R, C-Q, D-P
on waxing the frequency of a tuning fork decreases and on filing the frequency of a tuning fork increases .
so in option A on waxing P frequency of P decreases and as given beats are also decreased so fork P was having higher frequency then fork Q , so
frequency of fork Q=2806
so Q=6
in option D on filing Q no of beats are increased means that Q is having higher frequency so
frequency of Q=280+6
Q=6
so the answer containing these 2 is B

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