A tuning fork produces 8 beats /s with a sonometer wire. When tension in the wire is increased by 21% again 8 beats/s produced with the same tuning fork, the frequency of the tuning fork is
A
168Hz
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B
176Hz
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C
328Hz
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D
336Hz
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Solution
The correct option is B168Hz
From first condition,
ftf−fsono=8 ....(1)
From second condition,
−ftf+f′sono=8 ....(2)
f′sonofsono=√1.21TT=1.1
f′sono=1.1×fsono
Now add equation (1) and (2), and substituting value of f′sono, we will get: