A tuning fork produces four beats per second with $49 c m$ and $50 c m$ lengths of a stretched wire of a sonometer. The frequency of the fork is

196 H z

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296 H z

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396 H z

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693 H z

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Solution

The correct option is C $396 H z$
$\frac{v}{98} - \frac{v}{100} = 8 o r v = 4 \times 98 m / s f_{2} = 400 H z, f_{1} = 392 H z$
$∴$ Using fork which produces $4$ beats with these wires has frequency $396 H z$

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A tuning fork produces four beats per second with 49 cm and 50 cm lengths of a stretched wire of a sonometer. The frequency of the fork is

The correct option is C 396 Hzv98−v100=8or v=4×98 m/s f2=400 Hz, f1=392 Hz∴ Using fork which produces 4 beats with these wires has frequency 396 Hz

A tuning fork produces four beats per second with $49 c m$ and $50 c m$ lengths of a stretched wire of a sonometer. The frequency of the fork is

The correct option is C $396 H z$
$\frac{v}{98} - \frac{v}{100} = 8 o r v = 4 \times 98 m / s f_{2} = 400 H z, f_{1} = 392 H z$
$∴$ Using fork which produces $4$ beats with these wires has frequency $396 H z$