Question

A TV tower has a height of 100 m. The average population density around the tower is 1000 per $k{m}^2$. The radius of the earth is $6.4\times {10}^6$m. The population covered by the tower is

• A. $2\times {10}^6$
• B. $3\times {10}^6$
• C. $4\times {10}^6$
• D. $6\times {10}^6$

Answer 1

The correct option is C $4\times {10}^6$

Population covered =$2\pi hR\times$Population density
$=2\pi \times 100\times 6.4\times {10}^6\times \frac{1000}{({10}^3{)}^2}=4\times {10}^6$