Question

A TV tower has a height of 100m. The population density around the TV if the population covered is 60.288 lac, is :

• A. $5\times {10}^{3}k{m}^{-2}$
• B. $1.5\times {10}^{3}k{m}^{-2}$
• C. $7.5\times {10}^{3}k{m}^{-2}$
• D. ${10}^{4}k{m}^{-2}$

Answer 1

The correct option is B $1.5\times {10}^{3}k{m}^{-2}$

Total area over which the transmission could be viewed is $2\pi hR=2\times 3.14\times 0.1\times 6.37\times {10}^{3}k{m}^2=40\times {10}^{2}k{m}^2$
Thus the population density is given as $\frac{60.288\times {10}^5}{40\times {10}^2}=1.5\times {10}^{3}k{m}^{-2}$