A two-step mechanism has been suggested for the reaction of nitric oxide and bromine. NO(g)+Br2(g)K1−→NOBr2(g) NOBr2(g)+NO(g)K2−→2NOBr(g) The observed rate law is, rate =k[NO]2[Br2]. Hence, the rate-determining step is :
A
NO(g)+Br2(g)→NOBr2(g)
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B
NOBr2(g)+NO(g)→2NOBr(g)
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C
2NO(g)+Br2(g)→2NOBr(g)
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D
none of these
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Solution
The correct option is BNOBr2(g)+NO(g)→2NOBr(g) NO(g)+Br2(g)k1⇌NOBr2(g) .....(i) NOBr2(g)+NO(g)k2−−−→RDS2NOBr2(g) .....(ii) Rate = k2[NOBr2][NO] Since, NOBr2 is the reactive intermediate, so its constant ratio is dertermined from step (i). k1orkeq=[NOBr2][NO][Br2] or [NOBr2]=k1[NO][Br2] Substitute the [NOBr2] in step (iii), ∴ Rate = k1k2[NO]2[Br2]=K[NO]2[Br2]