Question

A U-tube containing a liquid is accelerated horizontally with a constant acceleration $a_o$. If the separation betwen the vertical limbs is l . The difference in the heights of the liquid in the two arms is:

• A. $\frac{a_{o}l}{g}$
• B. $\frac{a_{o}g}{l}$
• C. $\frac{g}{a_{o}l}$
• D. $\frac{l}{a_{o}g}$

Answer 1

The correct option is A $\frac{a_{o}l}{g}$

change in pressure in x direction similar to in Y direction
$P_A=0$
$P_B=f{a}_{0}L$
So,
Height of liquid in B$=fgH=P_B$
$=fgH=f{a}_{0}L$
$H=\frac{a_{0}L}{g}$