wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A uniform chain of length l and mass m lies on a smooth table. A very small part of this chain hangs from the table. It begins to fall under the weight of the hanging end. Find the velocity of the chain when the length of the hanging part becomes y.

A
ygl
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
2ygl
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
y2gl
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
yg2l
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A ygl
Let, mass of chain =m
When length of the hanging part =y,
mass of hanging part of chain =myl
According to principle of energy conservation :
Loss in gravitational potential energy of hanging part = Gain in KE of the whole chain
(myl)g(y2)=12mv2
(because COM of hanging part has fallen by a distance of y2)
v2=gy2lv=ygl

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon