A uniform chain of length L is lying on the horizontal table- If the content the chain and the table top is - - what is the maximum length of the edge of the table without disturbing the rest of the chain on the table-

The correct option is B μ L(1 + μ) [ mass per unit length= M L #160;; ...

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Standard XII

Physics

Net Force

A uniform cha...

Question

A uniform chain of length L is lying on the horizontal table. If the content the chain and the table top is ' $μ$ ' what is the maximum length of the edge of the table without disturbing the rest of the chain on the table?

\frac{L}{(l + μ)}

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\frac{μ L}{(1 + μ)}

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\frac{L}{(1 - μ)}

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none of these

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Solution

The correct option is B $\frac{μ L}{(1 + μ)}$
$\begin{matrix} m a s s p e r u n i t l e n g t h = \frac{M}{L} l = l e m g t h o f h a n g i n g m a s s L - l = m a s s o n t a b l e s u r f a c e S o, \frac{u M}{L (L - l) g} = \frac{M}{L \cdot l \cdot g μ (L - l)} = l o n s o l v i n g l = \frac{μ L}{1 + μ} \end{matrix}$
Hence,
option $(B)$ is correct answer.

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A uniform chain of length L is lying on the horizontal table. If the content the chain and the table top is 'μ' what is the maximum length of the edge of the table without disturbing the rest of the chain on the table?

The correct option is B μL(1+μ)massperunitlength=MLl=lemgthofhangingmassL−l=massontablesurfaceSo,uML(L−l)g=ML⋅l⋅gμ(L−l)=lonsolvingl=μL1+μHence,option (B) is correct answer.

A uniform chain of length L is lying on the horizontal table. If the content the chain and the table top is ' $μ$ ' what is the maximum length of the edge of the table without disturbing the rest of the chain on the table?