A uniform conducting wire offers a resistance of 60 Ω. It is cut into 12 equal parts and 6 of them are connected in parallel and remaining 6 are connected in series. This parallel bundle is connected in series with the series chain. Then, find the net resistance.

30.84 Ω

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32.84 Ω

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29.84 Ω

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31.84 Ω

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Solution

The correct option is A
30.84 Ω

Each part will have r/12 resistance = 60 Ω/12 = 5 Ω

NET RESISTANCE Of 6 resistances in parallel = 5/6 Ω

NET RESISTANCE Of 6 resistances in series = 30 Ω

Thus, net resistance of parallel bundle connected in series with the series chain

R = 5/6 Ω + 30 Ω

= 185/6 Ω

= 30.84 Ω

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