A uniform conductor of resistance R is cut into $20$ equal pieces half of them are joined is series and the remaining half of them are connected in parallel if the two combination are joined in series

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Solution

let the resistance of each piece $R_{0}$
where $R_{0}$ $R / 20$
so we have 10 such resistance joined in resistance thus giving us an $R_{e q s e r i e s} = 10 \times R_{0} = 10 R_{0}$
the 10 resistance joined in parallel which gives us an equilance
$R_{e q p a r a l l e l} = 10 / R_{0} t h i s c o m b i n a t i o n j o i n e d i n s e r i e s R_{n e t} = R_{0} / 10 = 10 R_{0}$
$R_{n e t} = 101 R_{0} / 10 = 101 \times R / 200$

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A uniform conductor of resistance R is cut into 20 equal pieces half of them are joined is series and the remaining half of them are connected in parallel if the two combination are joined in series

let the resistance of each piece R0whereR0 R/20so we have 10 such resistance joined in resistance thus giving us an Reqseries=10×R0=10R0the 10 resistance joined in parallel which gives us an equilance Reqparallel=10/R0thiscombinationjoinedinseriesRnet=R0/10=10R0Rnet=101R0/10=101×R/200

A uniform conductor of resistance R is cut into $20$ equal pieces half of them are joined is series and the remaining half of them are connected in parallel if the two combination are joined in series