A uniform electric field $E = 2 \times 10^{3} N C^{- 1}$ is acting along the positive x-axis. The flux through the same square if the line normal to tis plane makes a $60^{o}$ angle with the x-axis is

30 N C^{- 1} m^{2}

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10 N C^{- 1} m^{2}

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20 N C^{- 1} m^{2}

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25 N C^{- 1} m^{2}

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Solution

The correct option is B $10 N C^{- 1} m^{2}$
When normal to the plane makes an angle of $60^{o}$ with x-axis, then $θ = 6 0^{o}$
$ϕ = E s E s cos θ = 2 \times 10^{3} \times 10^{- 2} cos 60^{o} N C^{- 1} m^{2} = 10 N C^{- 1} m^{2}$

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A uniform electric field E=2×103NC−1 is acting along the positive x-axis. The flux through the same square if the line normal to tis plane makes a 60o angle with the x-axis is

The correct option is B 10NC−1m2When normal to the plane makes an angle of 60o with x-axis, then θ=60oϕ=EsEscosθ=2×103×10−2cos60oNC−1m2=10NC−1m2

A uniform electric field $E = 2 \times 10^{3} N C^{- 1}$ is acting along the positive x-axis. The flux through the same square if the line normal to tis plane makes a $60^{o}$ angle with the x-axis is

The correct option is B $10 N C^{- 1} m^{2}$
When normal to the plane makes an angle of $60^{o}$ with x-axis, then $θ = 6 0^{o}$
$ϕ = E s E s cos θ = 2 \times 10^{3} \times 10^{- 2} cos 60^{o} N C^{- 1} m^{2} = 10 N C^{- 1} m^{2}$