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Equipotential Surfaces

A uniform ele...

Question

A uniform electric field in the plane of the paper is shown in the figure. Here A, B, C, D are the points on the circle. $V_{A}, V_{B}, V_{C}, V_{D}$ are the potentials at those points respectively. Then :

V_{A} = V_{C}, V_{B} = V_{D}

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V_{A} = V_{C}, V_{B} > V_{D}

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V_{A} > V_{C}, V_{B} > V_{D}

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V_{A} = V_{B}, V_{C} = V_{D}

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V_{C} > V_{B} = V_{A} > V_{D}

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Solution

The correct option is E $V_{C} > V_{B} = V_{A} > V_{D}$
Electric field is defined as the gradient of potential i.e.
$E = - \frac{d V}{d r}$
Hence, electric field lines are directed from points at higher potential to points at lower potential.
$∴ V_{C} > V_{B} = V_{A} > V_{D}$

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A uniform electric field in the plane of the paper is shown in the figure. Here A, B, C, D are the points on the circle. VA,VB,VC,VD are the potentials at those points respectively. Then :

The correct option is E VC>VB=VA>VDElectric field is defined as the gradient of potential i.e.E=−dVdr Hence, electric field lines are directed from points at higher potential to points at lower potential.∴VC>VB=VA>VD

A uniform electric field in the plane of the paper is shown in the figure. Here A, B, C, D are the points on the circle. $V_{A}, V_{B}, V_{C}, V_{D}$ are the potentials at those points respectively. Then :

The correct option is E $V_{C} > V_{B} = V_{A} > V_{D}$
Electric field is defined as the gradient of potential i.e.
$E = - \frac{d V}{d r}$
Hence, electric field lines are directed from points at higher potential to points at lower potential.
$∴ V_{C} > V_{B} = V_{A} > V_{D}$