A uniform metre rule of weight $10 g f$ is pivoted at its $0$ mark. What moment of force depresses the rule?

5 g f

c m

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10 g f

c m

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100 g f

c m

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500 g f

c m

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Solution

The correct option is D $500 g f$ $c m$
As we have a $10 g f$ weight at $0$ mark and it will have a perpendicular distance of $50 c m$ from point $O$ that is from the centre of the scale we will have moment of force = $50 \times 10 g f c m$ = $500 g f c m$ . Hence it will have $500 g f c m$ to depress the rule.

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A uniform metre rule of weight 10gf is pivoted at its 0 mark. What moment of force depresses the rule?

The correct option is D 500gf cmAs we have a 10gf weight at 0 mark and it will have a perpendicular distance of 50cm from point O that is from the centre of the scale we will have moment of force = 50×10gfcm = 500gfcm. Hence it will have 500gfcm to depress the rule.

A uniform metre rule of weight $10 g f$ is pivoted at its $0$ mark. What moment of force depresses the rule?