A uniform ring of mass m is lying at a distance $\sqrt{3}$ a from the centre of a sphere of 8mass M just over the sphere (where a is the radius of the ring as well as that of the msphere), Then magnitude of gravilational force between them is

\frac{G M m}{8 a^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{G M m}{\sqrt{3} a^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{3} \frac{G M m}{a^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\sqrt{3} \frac{G M m}{8 a^{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\sqrt{3} \frac{G M m}{8 a^{2}}$
The sphere for outside objects can e treated as point mass at a distance $\sqrt{3} a$ .

$F = \frac{G M m \sqrt{3} a}{(a^{2} + (\sqrt{3} a)^{2})^{\frac{3}{2}}}$

$F = \frac{\sqrt{3} G M m}{8 a^{2}}$

option D is correct.

Suggest Corrections

Similar questions

A uniform ring of mass m is lying at a distance 1.73 a from the centre of a sphere of mass M just over the sphere where a is the small radius of the ring as well as that of the sphere. Then gravitational

force exerted is

A uniform ring of mass ‘m’ and radius ‘a’ is placed directly above a uniform sphere of mass ‘M’ and of equal radius. The centre of the ring is at a distance $\sqrt{3} a$ from the centre of the sphere. The gravitational force exerted by the sphere on the ring is

Q. A uniform ring of mass

m

and radius

r

is placed directly above a uniform sphere of mass

M

and of equal radius. The centre of the ring is directly above the centre of the sphere at a distance

r \sqrt{3}

as shown in the figure.
The gravitational force exerted by the sphere on the ring will be

Q. A uniform ring of mass

m

and radius a is placed directly above a uniform sphere of mass

M

and of equal radius. The centre of the ring is at a distance

\sqrt{3} a

from the centre of the sphere. Find the gravitational force exerted by the sphere on the ring.

Join BYJU'S Learning Program

A uniform ring of mass m is lying at a distance √3 a from the centre of a sphere of 8mass M just over the sphere (where a is the radius of the ring as well as that of the msphere), Then magnitude of gravilational force between them is

The correct option is D √3GMm8a2The sphere for outside objects can e treated as point mass at a distance √3a. F=GMm√3a(a2+(√3a)2)32F=√3GMm8a2option D is correct.

A uniform ring of mass m is lying at a distance $\sqrt{3}$ a from the centre of a sphere of 8mass M just over the sphere (where a is the radius of the ring as well as that of the msphere), Then magnitude of gravilational force between them is

The correct option is D $\sqrt{3} \frac{G M m}{8 a^{2}}$
The sphere for outside objects can e treated as point mass at a distance $\sqrt{3} a$ .

$F = \frac{G M m \sqrt{3} a}{(a^{2} + (\sqrt{3} a)^{2})^{\frac{3}{2}}}$

$F = \frac{\sqrt{3} G M m}{8 a^{2}}$

option D is correct.