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Question

A uniform rod of 20 kg is hanging in a horizontal positions with the help of two threads. It show supportive a 40 kg mass as shown in the figure. Find the tensions developed in each thread.

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Solution

Free body diagram of the rod is shown in the figure.
Translational equilibrium requires
Fy=0T1+T2=400+200=600 N....(i)
Rotational equilibrium: Applying the condition about A, we get T2.
τA=0400(l/4)200(l/2)+T2l=0
T2=200 N
From equation (i)
T1=400 N.
786599_795905_ans_bd0e01f57d4a45b89d4820ba59032bc6.jpg

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