A uniform rod of length 60cm and mass 6kg is acted upon by two forces as shown in the diagram. The force exerted by 45cm part of the rod on 15cm part of the rod is
The force exerted by 45cm part of the rod on 15cmart of the rod is given as,
F=F1×1560+F2×4560
F=21×1560+45×4560
F=45×1560+21×4560
F=27N