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Question

A uniform rod of length 'l' is kept vertically on a horizontal smooth surface at a point O. If it is rotated slightly and released, it falls down on the horizontal surface. the lower end will remain

A
at O
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B
at a distance less than l/2 from O
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C
at a distance l/2 from O
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D
at a distance larger than l/2 from O
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Solution

The correct option is C at a distance l/2 from O
Fext=macm

Along x-direction

Fext=0

ac.m=0 (along x-direction)

Vc.m= Constant (along x-direction)

Initial velocity of centre of mass is 0.

(Vc.m)final=0 (along x-direction)

x coordinate of centre of mass will remain at same point.



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