Question

A uniform rod of length l is placed symmetrically on two walls as shown in figure. The rod is in equilibrium. If $N_1$ and $N_2$ are the normal forces exerted by the walls on the rod then

• A. $N_1>N_2$
• B. $N_1<N_2$
• C. $N_1=N_2$
• D. $N_1$ and $N_{12}$ would in the vertical directions.

Answer 1

The correct option is C $N_1=N_2$

$\begin{array}{c}\text{Correct option is (C)}\\ \text{If it is in equilibrium then;}\\ \begin{array}{c}{\tau }_{\text{net}}=0\\ N_1\left(\frac{l}{t}\right)-N_2\left(1/4\right)=0\\ N_1=N_2\end{array}\end{array}$