CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

A uniform rope lies on a table with some portion hanging. The rope begins to slide when the length of hanging part is 25% of entire length. The coefficient of friction between rope and table is:

A
0.33
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.25
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0.2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.33
Let the total length of the rope be 'x' and, mass per unit length of the rope be 'm'
So, the length of the hanging rope = =25100x=0.25x
Mass of the hanging part of the rope = 0.25xm
Mass of the rope on the table = 75100xm=0.75xm
Let the coefficient of friction between the rope and the table be μ
Using equation of motion,
weight of rope on the table = weight of the hanging rope
μ(0.75)mxg=0.25mgxμ=0.33


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservative Forces and Potential Energy
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon