A uniform rope of total length l is at rest on a table with fraction f of its length hanging (see figure). If the coefficient of friction between the table and the chain is μ then which of the following relation is true:
A
f=μ
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B
f=1/(1+μ)
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C
f=1/(1+1μ)
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D
f=1/(μ+1/μ)
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Solution
The correct option is Cf=1/(1+1μ) Weight of portion hanging from table λfLg where λ is mass per unit length
weight of portion table is λ(1−f)Lg
Frictional force Ffr=λ(1−f)Lgμ
equating weight of hanging portion with frictional force ,μ=f1−f