Question

A uniform thin rod suffers a longitudinal strain of $4\times {10}^{-4}$ and if the material of the rod has Poisson's ratio of 0.5, then percentage change in volume is

• A. 0.0
• B. $(4\times {10}^{-4}{)}^{\frac{1}{3}}$
• C. $(4\times {10}^{-4}{)}^{\frac{2}{3}}$
• D. $(2\times {10}^{-4}{)}^{\frac{1}{3}}$

Answer 1

The correct option is A 0.0

$\frac{\Delta V}{V}=(1-2\nu )\frac{\Delta l}{l}$
$=(1-2\times 0.5)\frac{\Delta l}{l}$
$\frac{\Delta V}{V}=0$