Question

A uniform wire of resistance $9\Omega$ is cut into 3 equal parts. They are connected in the form of equilateral triangle ABC. A cell of emf 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is

• A. 2 V
• B. 0.5 V
• C. 3 V
• D. 1 V

Answer 1

The correct option is D 1 V

The circuit can be drawn as follows


Given
$V_{BC}=2V$

In branch BAC, as both resistances are same so potential drop across both resistances will also be same

$V_{AB}=V_{BC}/2=1V$

Hence, option (a) is correct.