A uniform wire when connected directly across a 200 V line, produces heat H per second. If the wire is divided into n parts and all parts are connected in parallel across a 200 V line, the heat produced per second will be
A
H
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B
nH
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C
Hn2
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D
n2H
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Solution
The correct option is Bn2H Initially the heat produced in wire is H=V2R when the wire is divided into n parts hence, resistance of each part will be Rn Now, all parts are connected in parallel across a 200 V line, the equivalent heat is Heq=H1+H2+........+Hn Heq=V2R1+V2R2+........+V2Rn Heq=V2[1R1+1R2+........+1Rn] Heq=V2⎡⎢
⎢
⎢⎣1R1n+1R2n+........+1Rnn⎤⎥
⎥
⎥⎦ ⇒Heq=nV2[1R1+1R2+........+1Rn] ⇒Heq=n(nH)=n2H