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Question

(a) Using Gauss law, drive an expression for the electric field intensity at any point outside a uniformly charged thin spherical shell of radius R and charge density σC/m2. Draw the field lines when the charge density of the sphere is (i) positive, (ii) negative


(b)A uniformly charged conducting sphere of 2×5m in diameter has a surfaces density of 100mC/m2 . Calculate the (i) charge on the sphere (ii) total electric flux passing through the sphere.

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Solution

Let a thin spherical shell be considered of radius R with a centre O. Let +q charge be uniformly distributed over the surface of shell.

Acc. to Gauss Law;
E.ds=qε0

E.^nds=qε0

Eds=qε0 [^n.^n=1]

E(4πr2)=qε0

E=14πr2.qε0

At any point at the surface of the shell; r=R

E=14πR2.qε0

q=4πR2σ

E=14πr2.4πR2σε0

E=σε0

a) i) Refer fig. (2)

Field lines when charge density of sphere is positive.

ii) Refer fig. (3)

Field lines when charge density of sphere is negative.

b) Diameter of sphere =2.5m
Radius =1.25m
Charge density, σ=100μCm2=104C/m3

i) Total charge, q=4πR2σ=1.96×103C

ii) Total flux, ϕ=qε0=2.21×108Nm2C1





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