You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Nernst Equation

A variable, o...

Question

A variable, opposite external potential ( $E_{e x t}$ ) is applied to the cell
$Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$ , of potential 1.1 V. When $E_{e x t}$ < 1.1 V amd $E_{e x t}$ > 1.1 V respectively electron flow from:

cathode to anode in both cases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

anode to cathode and cathode to anode

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

anode to cathode in both cases

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cathode to anode and anode to cathode

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D anode to cathode and cathode to anode
When $E_{e x t} <$ 1.1 V, the electrons will flow from anode to cathode, the cell will act as the galvanic cell.

when $E_{e x t} >$ 1.1 V, electrons will flow from cathode to anode and the cell will act as electrolytic cell.

Hence, option B is correct.

Suggest Corrections

Similar questions

Q. Assertion :For the Daniell cell,

Z n | Z n^{2 +} | | C u^{2 +} | C u

with

E_{c e l l} = 1.1 v o l t

, the application of opposite potential greater than

1.1 V

results into flow of electrons from cathode to anode. Reason:

Z n

is deposited at anode and

C u

is dissolved at cathode.

Q. Assertion :For the Daniel cell,

Z n | Z n^{2 +} | | C u^{2 +} | C u

with

E_{c e l l} = 1.1 V

, the application of opposite potential greater than

1.1 V

results into flow of electron from cathode to anode. Reason:

Z n

is deposited at anode, and

C u

is deposited at cathode.

Q. Assertion :For a Daniell cell :

Z n | Z n^{2 +} | | C u^{2 +} | C u

with

E_{c e l l} = 1.1 V

the application of opposite potential greater than 1.1 V results into the flow of electrons from cathode an anode. Reason: Zn is deposited at anode and Cu is dissolved at cathode.

Q. When a galvanic cell is connected to an external volatge supply (

E_{e x t}

), the electrons flow from cathode to anode because

In electrolytic cell flow of electron is from :
a)cathod to anode in solution
b)cathode to anode through external supply
c)cathode to anode through internal supply
d)anode to cathode to internal supply

[Pls explain Concept and answer]

Join BYJU'S Learning Program

A variable, opposite external potential (Eext) is applied to the cell Zn|Zn2+(1M)||Cu2+(1M)|Cu, of potential 1.1 V. When Eext < 1.1 V amd Eext > 1.1 V respectively electron flow from:

The correct option is D anode to cathode and cathode to anodeWhen Eext<1.1 V, the electrons will flow from anode to cathode, the cell will act as the galvanic cell.when Eext>1.1 V, electrons will flow from cathode to anode and the cell will act as electrolytic cell.Hence, option B is correct.

A variable, opposite external potential ( $E_{e x t}$ ) is applied to the cell
$Z n | Z n^{2 +} (1 M) | | C u^{2 +} (1 M) | C u$ , of potential 1.1 V. When $E_{e x t}$ < 1.1 V amd $E_{e x t}$ > 1.1 V respectively electron flow from: