Question

A varies directly as B and inversely as C . A is 12 when B is 6 and C is 2 . What is the value of A when B is 12 and C is 3 .

• A. 4
• B. 8
• C. 12
• D. 16

Answer 1

The correct option is D 16

From given, we have,

$A\propto B,A\propto \frac{1}{C}$

$\Rightarrow A\propto \frac{B}{C}$

$\therefore A=\frac{kB}{C}$

where, $k$ is a constant

$12=\frac{k\left(6\right)}{2}$

$\therefore k=4$

Now,

$A=\frac{4\times 12}{3}=16$