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Question 10
Let y varies directly as x. if y = 12 when x = 4, then write a linear equation. What is the value of y when x = 5?
 


Solution

Given that, y varies directly as x.
i.e…  yxy=kx    …(i)  [where, k = arbitrary constant]
Given, y = 12 and x = 4 (substituting these values in Eq(i))
12 = 4k
k=124   
k = 3.
On Putting the value of k in eq.(i) we get
y = 3x         …(ii)
When x = 5, from Eq. (ii), we get,
y = 3 × 5 y = 15
Hence, the value of y is 15.

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