A vehicle moves east with a speed of $50 m / s$ and then towards north with a speed of $50 m / s$ only. Total time taken by the body is $5 s$ . What is the average acceleration of the body?

0 m / s^{2}

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50 m / s^{2}

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14 m / s^{2}

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20.4 m / s^{2}

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Solution

The correct option is C $14 m / s^{2}$
Assume, East as positive $x -$ axis and North as positive $y -$ axis.
We can write the change in velocity as:
$Δ v = 50^j - 50^i$
Now,
$Δ v = 50^j - 50^i Δ a = \frac{Δ v}{t} = 10^j - 10^i | Δ a | = 10 \sqrt{2} = 14$

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A vehicle moves east with a speed of 50m/s and then towards north with a speed of 50m/s only. Total time taken by the body is 5s. What is the average acceleration of the body?

The correct option is C 14m/s2Assume, East as positive x−axis and North as positive y− axis.We can write the change in velocity as:Δv=50^j−50^iNow,Δv=50^j−50^iΔa=Δvt=10^j−10^i|Δa|=10√2=14

A vehicle moves east with a speed of $50 m / s$ and then towards north with a speed of $50 m / s$ only. Total time taken by the body is $5 s$ . What is the average acceleration of the body?

The correct option is C $14 m / s^{2}$
Assume, East as positive $x -$ axis and North as positive $y -$ axis.
We can write the change in velocity as:
$Δ v = 50^j - 50^i$
Now,
$Δ v = 50^j - 50^i Δ a = \frac{Δ v}{t} = 10^j - 10^i | Δ a | = 10 \sqrt{2} = 14$